Kyle H on Sun, 28 Nov 2004 13:21:07 -0600 (CST) |
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Re: [eia] PPs for a victorious multinational force |
Yes, if you read the email I sent, I included this amendment. kdh ----- Original Message ----- From: "J.J. Young" <jjy@xxxxxxxxxxx> To: "public list for an Empires in Arms game" <eia@xxxxxxxxx> Sent: Sunday, November 28, 2004 2:14 PM Subject: Re: [eia] PPs for a victorious multinational force > I seem to recall some debate and modification of the criteria used to select > the "leading victor". Specifically, I think we decided to make number of > corps the first thing to be looked at, then the army leader as the > tie-breaker. > > -JJY > > ----- Original Message ----- > From: "Kyle H" <menexenus@xxxxxxx> > To: "public list for an Empires in Arms game" <eia@xxxxxxxxx> > Sent: Sunday, November 28, 2004 11:35 AM > Subject: [eia] PPs for a victorious multinational force > > > > > > This was our first battle with combined allies in this game. > > > > As I understand the rules for PPs we agreed upon, the "most > > > > prominent" ally in the battle (to be determined by number of > > > > corps involved, ties to determined by the nationality of the > > > > army leader) receives PPs equal to _half_ of the usual number > > > > of PPs gained by a single victor, fractions rounded up. > > > > Other allies involved in the battle gain +1 PP each. Is this > > > > correct ? If so, the both Great Britain and Austria gain +1 > > > > PP, France loses -1 PP. > > > > > > How can more than one PP be awarded? Shouldn't JJ receive one and I > > > none? > > > > > > > For Nate's benefit (and to refresh all of our memories), we decided in > > the last EIA game that the rules for dividing PPs for a multinational > force > > were open to competing interpretations. After much debate and discussion, > > we ended up accepting the following house rule on PPs for a victorious > > multinational force. (JJ's description of the rule we adopted is not > > completely accurate.) What follows is the proposal we adopted for > assigning > > PPs to a victorious multinational force after a field combat. > > > > kdh > > > > <snip> > > While I do not think it is possible to construct a system for PP gains > > that is perfectly zero-sum, I don't think we need to strive for perfection > > here. If a few PPs are created or lost here or there, we can live with > > that. (After all, PPs are created all the time when someone wins a siege > > battle.) Here's what I think would be a reasonably equitable way to > > distribute PPs to a victorious multinational force: > > > > a.. Choose one country as the "lead" country of the multi-national > force. > > (This concept will be fleshed out more below.) > > b.. Count the number of corps that participated on the losing side of > the > > battle, and count the number of corps that the "lead" country of the > > victorious side had in the battle. (Any corps that starts the battle with > > more than 19 factors should be counted as 2 corps for this purpose.) > Choose > > the *lesser* of these two numbers. > > c.. Multiply this number by 1/2 and round up. The result is the number > of > > PPs gained by the "lead" country of the multi-national force (to a maximum > > of 3). All other victorious countries who had corps in the battle gain > > exactly 1 PP (regardless of how many corps they had). > > > > Now, of course, we would need rules to determine which country is the one > > that "leads" the multi-national force, but these should not be hard to > > develop. Here's what I suggest: > > > > Determining which country is the "leader" of the multi-national force: > > a.. If the stack has no leader, then the "lead" country would be the > major > > power with the most corps in the stack (including controlled minor free > > state corps). > > b.. If the stack is commanded by a leader, the nationality of that > leader > > determines the "lead" country of the multi-national force. (If Swedish > > Bernadotte is in command, then the major power controlling Sweden would be > > the "lead" country.) > > c.. If the stack has no leader and contains an equal number of corps on > > both sides, then the "lead" country is the one whose corps contain the > most > > regular factors. (By "regular" I mean factors whose morale is 3 or > higher.) > > d.. If the stack contains no leader, has an equal number of corps, and > > also has an equal number of regular factors in those corps, then the > "lead" > > country would be determined by competitive die rolls. > > > > <snip> > > > > _______________________________________________ > > eia mailing list > > eia@xxxxxxxxx > > http://lists.ellipsis.cx/mailman/listinfo/eia > > > > > > > _______________________________________________ > eia mailing list > eia@xxxxxxxxx > http://lists.ellipsis.cx/mailman/listinfo/eia > _______________________________________________ eia mailing list eia@xxxxxxxxx http://lists.ellipsis.cx/mailman/listinfo/eia