Kyle H on Sun, 28 Nov 2004 10:50:44 -0600 (CST)

 [eia] PPs for a victorious multinational force

```> > This was our first battle with combined allies in this game.
> > As I understand the rules for PPs we agreed upon, the "most
> > prominent" ally in the battle (to be determined by number of
> > corps involved, ties to determined by the nationality of the
> > army leader) receives PPs equal to _half_ of the usual number
> > of PPs gained by a single victor, fractions rounded up.
> > Other allies involved in the battle gain +1 PP each.  Is this
> > correct ?  If so, the both Great Britain and Austria gain +1
> > PP, France loses  -1 PP.
>
> How can more than one PP be awarded?  Shouldn't JJ receive one and I
> none?
>

For Nate's benefit (and to refresh all of our memories), we decided in
the last EIA game that the rules for dividing PPs for a multinational force
were open to competing interpretations.  After much debate and discussion,
we ended up accepting the following house rule on PPs for a victorious
multinational force.  (JJ's description of the rule we adopted is not
completely accurate.)  What follows is the proposal we adopted for assigning
PPs to a victorious multinational force after a field combat.

kdh

<snip>
While I do not think it is possible to construct a system for PP gains
that is perfectly zero-sum, I don't think we need to strive for perfection
here.  If a few PPs are created or lost here or there, we can live with
that.  (After all, PPs are created all the time when someone wins a siege
battle.)  Here's what I think would be a reasonably equitable way to
distribute PPs to a victorious multinational force:

a.. Choose one country as the "lead" country of the multi-national force.
(This concept will be fleshed out more below.)
b.. Count the number of corps that participated on the losing side of the
battle, and count the number of corps that the "lead" country of the
victorious side had in the battle.  (Any corps that starts the battle with
more than 19 factors should be counted as 2 corps for this purpose.)  Choose
the *lesser* of these two numbers.
c.. Multiply this number by 1/2 and round up.  The result is the number of
PPs gained by the "lead" country of the multi-national force (to a maximum
of 3).  All other victorious countries who had corps in the battle gain
exactly 1 PP (regardless of how many corps they had).

Now, of course, we would need rules to determine which country is the one
that "leads" the multi-national force, but these should not be hard to
develop.  Here's what I suggest:

Determining which country is the "leader" of the multi-national force:
a.. If the stack has no leader, then the "lead" country would be the major
power with the most corps in the stack (including controlled minor free
state corps).
b..  If the stack is commanded by a leader, the nationality of that leader
determines the "lead" country of the multi-national force.  (If Swedish
Bernadotte is in command, then the major power controlling Sweden would be
c.. If the stack has no leader and contains an equal number of corps on
both sides, then the "lead" country is the one whose corps contain the most
regular factors.  (By "regular" I mean factors whose morale is 3 or higher.)
d.. If the stack contains no leader, has an equal number of corps, and
also has an equal number of regular factors in those corps, then the "lead"
country would be determined by competitive die rolls.

<snip>

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